Bài giảng Vi xử lý - Chương 3: Họ vi điều khiển 805 (Phần 2)

ꢁꢔꢕꢖꢆꢗꢘꢙꢚꢆꢛꢜꢆꢝꢞꢔꢟꢠꢆꢡꢢꢣꢆꢛꢚꢤꢥꢆꢁꢦꢆꢧꢨꢖꢙꢩꢆꢪꢫ

ꢬꢭꢆꢮꢯꢙꢆꢋꢔꢕꢙꢆꢛꢰꢆꢱ ꢲꢁꢆꢬꢎꢆꢧꢳꢁꢀꢪ

ꢀꢁꢂꢃꢄꢅꢆꢇ

ꢁꢈꢆꢉꢊꢆꢋꢊꢌꢍꢆꢎꢁꢊꢏꢄꢆꢐꢑꢒꢓ

ꢀ

ꢇꢴꢵꢆꢧꢶꢷꢆꢞꢕꢙꢚꢆꢐꢑꢒꢓ

ꢁ

ꢂꢃꢄꢅꢆꢇꢈꢉ

ꢇꢴꢵꢴꢓꢆꢀꢸꢡꢆꢞꢕꢙꢚꢆꢝꢹꢆꢚꢺꢡ

ꢇꢴꢵꢴꢻꢆꢀꢸꢡꢆꢞꢕꢙꢚꢆꢞꢖꢶꢙꢆꢞꢼ

ꢇꢴꢵꢴꢇꢆꢀꢸꢡꢆꢞꢕꢙꢚꢆꢡꢚꢖꢥꢽꢙꢆꢟꢾꢆꢞꢔꢕꢖ

ꢇꢴꢵꢴꢵꢆꢀꢸꢡꢆꢞꢕꢙꢚꢆꢿꣀꢔꢆꣁꢔꣂꢙꢆꢬooꢞꢠ

ꢇꢴꢵꢴꢒꢆꢀꢸꢡꢆꢞꢕꢙꢚꢆꢨꣃꢆꢙꢚꢸꢙꢚꢆꢡꢚươꢙꢩꢆꢛꢨ꣄ꢙꢚ

ꢇꢴꢵꢴꣅꢆꢪꢭꢛꢆꢝꢹꢆꢛꢚꢘꢆꢟ꣆

ꢊ

ꢋ ꢈꢉꢌꢍꢎꢅꢏꢐꢏꢅꢑꢒ ꢌꢄꢓꢇꢅꢔꢄꢕꢖꢅꢖꢗꢖꢅꢖꢘoꢈꢉꢅꢖꢙꢚꢅꢛꢓꢈꢌ

ꢜ

ꢝꢐꢏꢅꢛꢓꢈꢌꢅꢞꢈꢌꢅꢌꢟꢠꢈꢉꢅꢡꢕꢈꢅꢖꢌꢎꢈꢌꢅꢉꢌꢄꢅ

ꢖꢘꢢꢈꢉꢅꢖꢌꢐꢄꢅꢣꢤꢥꢅꢦꢝYꢧꢅꢨꢩꢧꢅꢪꢝꢫ

ꢬ

ꢓꢴꢆꢧ꣇ꢮꢆꢛ꣈ꢛꢆꢡꢸꢡꢆꢞꢕꢙꢚꢆꢝꢹꢆꢚꢺꢡ

ꢦꢉꢄꢞꢅꢭꢮꢅꢯꢰꢬꢀꢅꢔꢱꢄꢅꢖꢌꢢꢏꢌꢅꢎꢈꢌꢅꢀꢁꢅꢲꢳꢴꢫ

ꢵ

ꢽeꢖeꢏꢖꢄꢈꢉꢅꢨꢔeꢘꢷꢛoꢸ

ꢶ ꢂoꢅoꢔeꢘꢷꢛoꢸꢅꢸꢌeꢈꢅꢎꢆꢆꢄꢈꢉꢅꢎꢅꢚoꢭꢄꢖꢄꢔeꢅꢎꢈꢆꢅꢎꢅꢈeꢉꢎꢖꢄꢔeꢅ

ꢈꢇꢹꢺeꢘ

ꢶ ꢂoꢅoꢔeꢘꢷꢛoꢸꢅꢸꢌeꢈꢅꢭꢄꢉꢈꢭꢅꢎꢘeꢅꢖꢌeꢅꢭꢎꢹeꢅꢷoꢘꢅꢭꢇꢺꢖꢘꢎꢏꢖꢄoꢈ

ꢶ ꢨꢔeꢘꢷꢛoꢸꢅoꢏꢏꢇꢘꢭꢅꢸꢌeꢈꢅꢖꢌeꢅꢔꢎꢛꢇeꢅꢎꢷꢷeꢏꢖꢭꢅꢖꢌeꢅꢭꢄꢉꢈꢻ

ꢼ oꢔeꢘꢷꢛoꢸꢅꢸꢌeꢈꢅꢎꢆꢆꢄꢈꢉꢅꢖꢸoꢅꢚoꢭꢄꢖꢄꢔeꢭꢅyꢄeꢛꢆꢭꢅꢎꢅꢈeꢉꢎꢖꢄꢔeꢅ

ꢼ oꢘꢧꢅꢎꢆꢆꢄꢈꢉꢅꢖꢸoꢅꢈeꢉꢎꢖꢄꢔeꢭꢅꢉꢄꢔeꢭꢅꢎꢅꢚoꢭꢄꢖꢄꢔe

ꢼ oꢘꢧꢅꢭꢇꢺꢖꢘꢎꢏꢖꢅꢎꢅꢈeꢉꢎꢖꢄꢔeꢅꢷꢘoꢹꢅꢎꢅꢚoꢭꢄꢖꢄꢔeꢅꢎꢈꢆꢅꢉeꢖꢅꢎꢅꢈeꢉꢎꢖꢄꢔe

ꢼ oꢘꢧꢅꢭꢇꢺꢖꢘꢎꢏꢖꢅꢎꢅꢚoꢭꢄꢖꢄꢔeꢅꢷꢘoꢹꢅꢎꢅꢈeꢉꢎꢖꢄꢔeꢅꢎꢈꢆꢅꢉeꢖꢅꢎꢅꢚoꢭꢄꢖꢄꢔe

ꢶ ꢝoꢈꢭꢄꢆeꢘꢅꢖꢌeꢅoꢚeꢘꢎꢖꢄoꢈꢭꢅꢪꢅꢾꢅꢿꢧꢅꢎꢈꢆꢅꢪꢅꢼ ꢿ

ꢼ ꢝꢎꢈꢅoꢔeꢘꢷꢛoꢸꢅoꢏꢏꢇꢘꢅꢄꢷꢅꢿꢅꢄꢭꢅꢰꢅꣀ

ꢼ ꢝꢎꢈꢅoꢔeꢘꢷꢛoꢸꢅoꢏꢏꢇꢘꢅꢄꢷꢅꢪꢅꢄꢭꢅꢰꢅꣀ

ꣁ

ꢨꢔeꢘꢷꢛoꢸꢅꢽeꢖeꢏꢖꢄoꢈ

ꢶ ꢨꢔeꢘꢷꢛoꢸꢻꢅꢖꢌeꢅꢘeꢭꢇꢛꢖꢅꢄꢭꢅꢖooꢅꢛꢎꢘꢉeꢅꢦoꢘꢅꢖooꢅꢭꢹꢎꢛꢛꢫꢅꢖoꢅꢘeꢚꢘeꢭeꢈꢖꢅꢚꢘoꢚeꢘꢛy

ꢼ ꣂꣃꢎꢹꢚꢛeꢻꢅ꣄ ꢯꢅꣅꢅ꣆ꢅꢜ꣄ꢺꢄꢖꢅꢺꢄꢈꢎꢘyꢅꢈꢇꢹꢺeꢘꢅꣅ꣆ꢅꣁ

ꢶ ꢥꢌeꢈꢅꢎꢆꢆꢄꢈꢉꢅoꢚeꢘꢎꢈꢆꢭꢅꢸꢄꢖꢌꢅꢆꢄꢷꢷeꢘeꢈꢖꢅꢭꢄꢉꢈꢭꢧꢅoꢔeꢘꢷꢛoꢸꢅꢏꢎꢈꢈoꢖꢅoꢏꢏꢇꢘ꣇

ꢶ ꢨꢔeꢘꢷꢛoꢸꢅoꢏꢏꢇꢘꢭꢅꢸꢌeꢈꢅꢎꢆꢆꢄꢈꢉꢻ

ꢼ ꢁꢅꢚoꢭꢄꢖꢄꢔeꢅꢈꢇꢹꢺeꢘꢭꢅꢎꢈꢆꢅꢖꢌeꢅꢭꢇꢹꢅꢄꢭꢅꢈeꢉꢎꢖꢄꢔe

ꢼ ꢁꢅꢈeꢉꢎꢖꢄꢔeꢅꢈꢇꢹꢺeꢘꢭꢅꢎꢈꢆꢅꢖꢌeꢅꢭꢇꢹꢅꢄꢭꢅꢚoꢭꢄꢖꢄꢔe

ꢶ ꢨꢈꢅyoꢇꢘꢅoꢸꢈꢻꢅꢣꢘoꢔeꢅyoꢇꢅꢏꢎꢈꢅꢆeꢖeꢏꢖꢅoꢔeꢘꢷꢛoꢸꢅꢺyꢻ

ꢼ ꢝꢎꢘꢘyꢅꢄꢈꢖoꢅꢲꢤꢿꢅ꣈ ꢝꢎꢘꢘyꢅoꢇꢖꢅoꢷꢅꢲꢤꢿ

0

1

0

1

0

1

0

1

0

1

0

7

3

1

0

1

0

1

0

1

–4

– 5

+

– 6

7

ꢯ

ꢝꢐꢏꢅꢛꢓꢈꢌꢅꢪꢽꢽ

add a, byte

addc a, byte

; a ꢀ a + byte

; a ꢀ a + byte + C

ꢝꢐꢏꢅꢛꢓꢈꢌꢅꢈ꣉yꢅꢞꢈꢌꢅꢌꢟꢠꢈꢉꢅꢊꢅꢺꢄꢖꢅꢖꢘoꢈꢉꢅꢣꢤꢥꢻ

ꢝꢅ꣆ꢅꢀꢅꢈꢕꢇꢅꢑꢕꢖꢅ꣊ꢇꢞꢅꢏꢃꢈꢉꢅ꣋ꢅ ꣌꣌

ꢪꢝꢅ꣆ꢅꢀꢅꢈꢕꢇꢅꢏ꣍ꢅꢈꢌꢱꢅꢖꢢꢄꢅꢺꢄꢖꢅꢊ

ꢨꢩꢅ꣆ꢅꢀꢅꢈꢕꢇꢅꢏ꣍ꢅꢈꢌꢱꢅꢖ꣎ꢅꢺꢄꢖꢅꣁꢅꢹ꣉ꢅꢑꢌ꣏ꢈꢉꢅꢖ꣎ꢅꢺꢄꢖꢅꢵꢅꢅ

ꢌo꣐ꢏꢅꢈꢉꢟ꣑ꢏꢅꢛꢢꢄ꣒

꣓

꣔ꢓꢈꢌꢅꢪꢽꢽꢅꢔ꣉ ꢤ꣕ꢿꢿ

ADDA, Source ;A=A+SOURCE

ADDA,#6

ADDA,R6

ADD

;A=A+6

;A=A+R6

A,6

;A=A+[6] or A=A+R6

;A=A+[0F3H]

ADD

A,0F3H

SUBB A, Source ;A=A-SOURCE-C

SUBB

A,#6

A,R6

;A=A-6-(CY)

ꢀꢰ

;A=A-R6-(CY)

ꢤꢇꢺꢖꢘꢎꢏꢖꢅ

subtract with borrow

;A ꢀ A – 4F – C

SUBB A, byte

Example:

SUBB A, #0x4F

Notice that

There is no subtraction WITHOUT borrow.

Therefore, if a subtraction without borrow is desired,

it is necessary to clear the C flag.

Example:

Clr c

SUBB A, #0x4F

;A ꢀ A – 4F

ꢀꢀ

꣖ꢌ꣗ꢅꢆ꣘ꢅꢔꢱꢄꢅꢪꢽꢽ

mov a, #3FH

add a, #0D3H

ꢶ ꢝꢌoꢅꢺꢄꢕꢖꢅꢏꢐꢏꢅꢉꢄꢐꢅꢖꢘ꣙ꢅ

ꢏ꣚ꢎꢅꢏꢐꢏꢅꢏ꣛ꢅꢝꢧꢅꢪꢝꢅꢔ꣉ꢅ

ꢨꢩꢅꢭꢎꢇꢅꢑꢌꢄꢅꢛꢓꢈꢌꢅꢖꢌ꣜ꢅ

ꢌꢎꢄꢅꢡꢟ꣑ꢏꢅꢖꢌ꣝ꢏꢅꢖꢌꢄꣀ

0011 1111

1101 0011

0001 0010

C = 1

AC = 1

OV = 0

ꢀꢁ

ꢝꢃꢈꢉꢅꢏ꣍ꢅꢆ꣞ꢇꢅꢔ꣉ꢅꢖꢘ꣉ꢈꢅꢦꢨꢩꢫ

0111 1111 (positive 127)

2’s complement:

0000 0000 00 0

…

0111 0011 (positive 115)

1111 0010 (overflow

cannot represent 242 in 8

bits 2’s complement)

0111 1111 7F 127

1000 0000 80 -128

…

1000 1111 (negative 113)

1101 0011 (negative 45)

0110 0010 (overflow)

1111 1111 FF -1

0011 1111 (positive)

1101 0011 (negative)

0001 0010 (never overflows)

ꢀꢊ

ꢽeꢏꢄꢹꢎꢛꢅꢪꢆ꣟ꢇꢭꢖ

DA a

; decimal adjust a

꣕ꢭeꢆꢅꢖoꢅꢷꢎꢏꢄꢛꢄꢖꢎꢖeꢅꢿꢝꢽꢅꢎꢆꢆꢄꢖꢄoꢈ꣒ꢅ

ꢪꢆꢆꢭꢅ꣠ꢵ꣡ꢅꢖoꢅeꢄꢖꢌeꢘꢅꢌꢄꢉꢌꢅoꢘꢅꢛoꢸꢅꢈꢄꢺꢺꢛeꢅꢎꢷꢖeꢘꢅꢎꢈꢅꢎꢆꢆꢄꢖꢄoꢈꢅ

ꢖoꢅꢏꢘeꢎꢖeꢅꢎꢅꢔꢎꢛꢄꢆꢅꢿꢝꢽꢅꢈꢇꢹꢺeꢘ꣒

ꣂꣃꢎꢹꢚꢛeꢻ

mov a, #23h

mov b, #29h

add a, b

; a ꢀ 23h + 29h = 4Ch (wanted

52)

DA a

; a ꢀ a + 6 = 52

ꢀꢜ

꣖ꢌ꣗ꢅꢆ꣘ꢻꢅꢝꢃꢈꢉꢅꢁꢅꢭ꣢ꢅꢿꢝꢽ

ꢦꢹ꣣ꢄꢅꢭ꣢ꢅꢏ꣍ꢅꢜꢅꢑꢒꢅꢭ꣢ꢫ

ꢲꢨꢩ

ꢪꢧꢅꢜꢊꢳ

꣤ꢅꢈꢇꢹꢀꢅꢠꢅꢏꢐꢏꢅ꣏ꢅꢈꢌꢱꢅꢜꢰꢧꢅꢜꢀꢳ

ꢪꢽꢽ

ꢪꢧꢅꢜꢀꢳꢅ ꣤ꢅꢈꢇꢹꢁꢅꢠꢅꢏꢐꢏꢅ꣏ꢅꢈꢌꢱꢅꢜꢁꢧꢅꢜꢊꢳ

ꢪꢅꢅꢅ ꣤ꢅꢑꢕꢖꢅ꣊ꢇꢞꢅꢡ꣐ꢖꢅꢠꢅꢏꢐꢏꢅ꣏ꢅꢈꢌꢱꢅꢜꢰꢧꢅꢜꢀꢳ

ꢜꢀꢳꢧꢅꢪ

ꢽꢪ

ꢲꢨꢩ

C

ꢲꢨꢩ

ꢪꢧꢅꢜꢁꢳ

40H, 41H

42H, 43H

1234

+ 5678

-------------

(AC)

ꢪꢽꢽꢝ ꢪꢧꢅꢜꢰꢳ

ꢽꢪ

ꢪ

ꢲꢨꢩ

ꢜꢰꢳꢧꢪ

112

6912

ꢀꢬ

꣖꣗ꢈꢌꢅ꣥ꢅ꣆ꢅ꣦ꢅꢾꢅY

꣖ꢌ꣗ꢅꢆ꣘ꢻ ꣖꣗ꢈꢌꢅ꣥ꢅ꣆ꢅ꣦ꢅꢾꢅYꢅꢔꢱꢄꢅ꣥ꢧꢅ꣦ꢧꢅYꢅꢛ꣉ꢅꢭ꣢ꢅꢀꢅꢺyꢖeꢅꢖꢘoꢈꢉꢅ꣧ꢪꢲꢅꢈꢃꢄ꣒ꢅ

꣨ꢄꢞꢅꢭꢮꢅ꣦ꢅꢡꢟ꣑ꢏꢅꢏ꣞ꢖꢅꢠꢅꢜꢰꢳꢧꢅYꢅꢠꢅꢜꢀꢳꢧꢅꢔ꣉ꢅ꣥ꢅꢠꢅꢜꢁꢳ꣒

ꢝꢐꢏꢌꢅꢀꢻ

ꢲꢨꢩ ꢪꢧꢅꢜꢰꢌ

ꢪꢽꢽ ꢪꢧꢅꢜꢀꢌ

ꢲꢨꢩ ꢜꢁꢌꢧꢅꢪ

ꢝꢐꢏꢌꢅꢁꢻ

꣦

Y

꣥

ꣂ꣩꣕ ꢜꢰꢌ

ꣂ꣩꣕ ꢜꢀꢌ

ꣂ꣩꣕ ꢜꢁꢌ

ꢲꢨꢩ ꢪꢧꢅ꣦

ꢪꢽꢽ ꢪꢧꢅY

ꢲꢨꢩ ꣥ꢧꢅꢪ

ꢀꢵ

ꢝꢃꢈꢉꢅꢁꢅꢭ꣢ꢅꢀꢵꢅꢺꢄꢖ

꣖ꢌ꣗ꢅꢆ꣘ꢻ ꢝꢃꢈꢉꢅꢁꢅꢭ꣢ꢅꢀꢵꢅꢺꢄꢖꢅꢩꢎꢘ꣦ꢅꢔ꣉ꢅꢩꢎꢘYꢅꢦꢏ꣍ꢅꢡ꣙ꢎꢅ

ꢏꢌ꣪ꢅꢛ꣉ꢅ꣧ꢪꢲꢅꢈꢃꢄꢫ꣒ꢅꢝ꣞ꢖꢅꢑꢕꢖꢅ꣊ꢇꢞꢅꢔ꣉oꢅꢩꢎꢘ꣦꣒

꣤ꢅꢝꢐꢏꢅꢭ꣢ꢅꢀꢵꢅꢺꢄꢖꢅꢏ꣞ꢖꢅꢠꢅꢩꢎꢘ꣦ꢅꢔ꣉ꢅꢩꢎꢘ꣦ꢾꢀꢧꢅꢩꢎꢘYꢅꢔ꣉ꢅꢩꢎꢘYꢾꢀ

ꢲꢨꢩ ꢪꢧꢅꢩꢎꢘ꣦

ꢪꢽꢽ ꢪꢧꢅꢩꢎꢘY

ꢲꢨꢩ ꢩꢎꢘ꣦ꢧꢅꢪ

ꢲꢨꢩꢅ ꢪꢧꢅꢩꢎꢘ꣦ꢾꢀ

ꢪꢽꢽꢝ ꢪꢧꢅꢩꢎꢘYꢾꢀ

ꢏꢃꢈꢉꢅꢖꢘꢟꢱꢏ

꣤ꢅꢛ꣞yꢅꢺyꢖeꢅꢖꢌ꣞ꢚ

꣤ꢅꢏꢃꢈꢉꢅꢏꢐꢏꢅꢺyꢖeꢅꢖꢌ꣞ꢚ

꣤ꢅꢏ꣞ꢖꢅꢺyꢖeꢅꢖꢌ꣞ꢚ

꣤ꢅꢛ꣞yꢅꢺyꢖeꢅꢏꢎo

꣤ꢅꢏꢃꢈꢉꢅꢏ꣍ꢅꢈꢌꢱꢅꢏ꣚ꢎꢅꢚꢌ꣫ꢚꢅ

ꢲꢨꢩ ꢩꢎꢘ꣦ꢾꢀꢧꢅꢪ

꣤ꢅꢏ꣞ꢖꢅꢑꢕꢖꢅ꣊ꢇꢞ

ꢀꣁ

꣬ꢈꢏꢘeꢹeꢈꢖꢅꢎꢈꢆꢅꢽeꢏꢘeꢹeꢈꢖ

INC A

increment A

INC byte

INC DPTR

DEC A

increment byte in memory

increment data pointer

decrement accumulator

decrement byte

DEC byte

ꢶ ꣖ꢌeꢅꢄꢈꢏꢘeꢹeꢈꢖꢅꢎꢈꢆꢅꢆeꢏꢘeꢹeꢈꢖꢅꢄꢈꢭꢖꢘꢇꢏꢖꢄoꢈꢭꢅꢆoꢅꢂꢨ꣖

ꢎꢷꢷeꢏꢖꢅꢖꢌeꢅꢝꢅꢷꢛꢎꢉ꣒

ꢶ ꢂoꢖꢄꢏeꢅꢸeꢅꢏꢎꢈꢅoꢈꢛy ꣬ꢂꢝ꣧ꣂꢲꣂꢂ꣖ꢅꢖꢌeꢅꢆꢎꢖꢎꢅꢚoꢄꢈꢖeꢘꢧꢅ

ꢈoꢖꢅꢆeꢏꢘeꢹeꢈꢖ꣒

ꢀꢯ

꣔ꢓꢈꢌꢅ꣬ꢂꢝꢅꢔ꣉ꢅꢽꣂꢝ

DEC byte ;byte=byte-1

INC byte ;byte=byte+1

INC

R7

A

DEC

40H

; [40]=[40]-1

ꢀ꣓

꣔ꢓꢈꢌꢅꢽꣂꢝ

ꢝꢌ꣭ꢅꢒꢅꢔꢱꢄꢅꢽꢣ꣖꣧ꢅꢏꢌ꣪ꢅꢏ꣍ꢅꢛꢓꢈꢌꢅ꣬ꢂꢝꢅꢏ꣮ꢈꢅꢛꢓꢈꢌꢅꢽꣂꢝꢅꢖꢌ꣯ꢅ

ꢑꢌ꣏ꢈꢉꢅꢏ꣍꣒ꢅꢽoꢅꢡ꣍ꢅꢹꢇ꣢ꢈꢅꢖꢌ꣝ꢏꢅꢌꢄꢓꢈꢅꢔꢄꢓꢏꢅꢉꢄꢞꢹꢅꢽꢣ꣖꣧ꢅꢡꢄꢅ

ꢀꢅꢖꢌ꣯ꢅꢖꢎꢅꢚꢌꢞꢄꢅꢭꢮꢅꢆ꣘ꢈꢉꢅꢏꢌꢇ꣣ꢄꢅꢛꢓꢈꢌꢅꢭꢎꢇ

ꢲEꢀ ꢲꢳ꣉

꣊ꢆꢅꢔ꣋ꢮꢆꣁꢥꢛꢠꢆꢛꢚ꣌ꢷꢆꢡꢢꢣꢆꢲꢳꢧ꣍ꢆꢗꢔꢆꢓ

꣊ꢆꢡꢚ꣐ꢷꢆꢿ꣑oꢆ꣍꣎

ꢪOꢉ ꣍꣎꣏ꢆꢲꢳ꣉ꢆ

ꢀ꣒ꢄE ꣍꣎꣏ꢆ꣓ꢑ꣔꣔ꢁ꣏ꢆ꣕ꢎꢊꢳꢆ꣊ꢆꢄꣂꢖꢆꢛꢨ꣑ꢙꢆꢟưꣀꢔꢆꢛꢚ꣑ꢙꢚꢆ꣔꣔ꢆꢛꢚ꣄ꢆꢷꢚ꣋ꢔꢆꢮư꣖ꢙ

ꢲEꢀ ꢲꢳꢁ ꣊ꢆꢟoꢆꢗ꣇ꢆꢡ꣗ꢙꢩꢆꢷꢚ꣋ꢔꢆꢩꢔ꣋ꢮꢆꣁꢥꢛꢠꢆꢡꢣoꢆꢗꢔꢆꢓ

꣕ꢎꢊꢳ꣘ꢆ ꣙ꢛꢔꣂꢷꢆꢛ꣆ꢡ꣚

꣖ꢎꢅꢚꢌꢞꢄꢅꢉꢄꢞꢹꢅꢡꢄꢅꢀꢅꢘꢄ꣰ꢈꢉꢅꢏꢌoꢅꢏꢐꢏꢅꢺyꢖeꢅꢏꢎoꢅꢔ꣉ꢅꢺyꢖeꢅꢖꢌ꣞ꢚꢅ

ꢏ꣚ꢎꢅꢽꢣ꣖꣧꣤ꢅꢖꢇyꢅꢈꢌꢄ꣰ꢈꢅꢺyꢖeꢅꢏꢎoꢅꢦꢽꢣꢳꢫꢅꢏꢌ꣪ꢅꢺ꣙ꢅꢉꢄꢞꢹꢅꢈꢕꢇꢅ

ꢺyꢖeꢅꢖꢌ꣞ꢚꢅꢦꢽꢣ꣔ꢫꢅꢖꢘ꣉ꢈꢅꢆꢟꢱꢄꢅꢖ꣎ꢅꢰꢰꢳꢅꢭꢎꢈꢉꢅ꣌꣌ꢳ꣒

ꢁꢰ

Bài giảng Vi xử lý - Chương 3: Họ vi điều khiển 805 (Phần 2) - Hồ Trung Mỹ